Base | Representation |
---|---|
bin | 10100100100001011001… |
… | …010000101101010100001 |
3 | 12000002210112021022020211 |
4 | 110210023022011222201 |
5 | 141123244221400101 |
6 | 3001121330134121 |
7 | 204050122663363 |
oct | 24441312055241 |
9 | 5002715238224 |
10 | 1413231434401 |
11 | 4a5391335846 |
12 | 1a9a88421341 |
13 | a3361c1a9b7 |
14 | 4c5879bad33 |
15 | 26b64a79c51 |
hex | 1490b285aa1 |
1413231434401 has 4 divisors (see below), whose sum is σ = 1451426878612. Its totient is φ = 1375035990192.
The previous prime is 1413231434359. The next prime is 1413231434429. The reversal of 1413231434401 is 1044341323141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 477902603025 + 935328831376 = 691305^2 + 967124^2 .
It is a cyclic number.
It is not a de Polignac number, because 1413231434401 - 221 = 1413229337249 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1413231434101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19097722050 + ... + 19097722123.
It is an arithmetic number, because the mean of its divisors is an integer number (362856719653).
Almost surely, 21413231434401 is an apocalyptic number.
It is an amenable number.
1413231434401 is a deficient number, since it is larger than the sum of its proper divisors (38195444211).
1413231434401 is an equidigital number, since it uses as much as digits as its factorization.
1413231434401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38195444210.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1413231434401 its reverse (1044341323141), we get a palindrome (2457572757542).
The spelling of 1413231434401 in words is "one trillion, four hundred thirteen billion, two hundred thirty-one million, four hundred thirty-four thousand, four hundred one".
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