14132440401 has 4 divisors (see below), whose sum is σ = 18843253872. Its totient is φ = 9421626932.

The previous prime is 14132440393. The next prime is 14132440463. The reversal of 14132440401 is 10404423141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14132440401 - 2³ = 14132440393 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14132440801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355406731 + ... + 2355406736.

It is an arithmetic number, because the mean of its divisors is an integer number (4710813468).

Almost surely, 2^14132440401 is an apocalyptic number.

It is an amenable number.

14132440401 is a deficient number, since it is larger than the sum of its proper divisors (4710813471).

14132440401 is an equidigital number, since it uses as much as digits as its factorization.

14132440401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4710813470.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 14132440401 its reverse (10404423141), we get a palindrome (24536863542).

The spelling of 14132440401 in words is "fourteen billion, one hundred thirty-two million, four hundred forty thousand, four hundred one".