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14133034540043 = 41933730392697
BaseRepresentation
bin1100110110101001101010…
…0000001101110000001011
31212001002211110212210202022
43031222122200031300023
53323023423320240133
650020343150555055
72656035525315326
oct315523240156013
955032743783668
1014133034540043
114559871606651
1217030b0808a8b
137b697c7145b3
1436c0849717bd
15197975379998
hexcda9a80dc0b

14133034540043 has 4 divisors (see below), whose sum is σ = 14166764933160. Its totient is φ = 14099304146928.

The previous prime is 14133034540013. The next prime is 14133034540063. The reversal of 14133034540043 is 34004543033141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14133034540043 - 236 = 14064315063307 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14133034539985 and 14133034540012.

It is not an unprimeable number, because it can be changed into a prime (14133034540013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16865195930 + ... + 16865196767.

It is an arithmetic number, because the mean of its divisors is an integer number (3541691233290).

Almost surely, 214133034540043 is an apocalyptic number.

14133034540043 is a deficient number, since it is larger than the sum of its proper divisors (33730393117).

14133034540043 is an equidigital number, since it uses as much as digits as its factorization.

14133034540043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33730393116.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 14133034540043 its reverse (34004543033141), we get a palindrome (48137577573184).

The spelling of 14133034540043 in words is "fourteen trillion, one hundred thirty-three billion, thirty-four million, five hundred forty thousand, forty-three".

Divisors: 1 419 33730392697 14133034540043