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141332011433 = 314559097143
BaseRepresentation
bin1000001110100000001…
…0110101100110101001
3111111210200010001220222
42003220002311212221
54303421443331213
6144532123255425
713132224163364
oct2035002654651
9444720101828
10141332011433
1154a36266038
122348397a575
1310434827642
146baa4c30db
153a22b36808
hex20e80b59a9

141332011433 has 4 divisors (see below), whose sum is σ = 145891108608. Its totient is φ = 136772914260.

The previous prime is 141332011411. The next prime is 141332011489. The reversal of 141332011433 is 334110233141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141332011433 - 26 = 141332011369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141332010433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2279548541 + ... + 2279548602.

It is an arithmetic number, because the mean of its divisors is an integer number (36472777152).

Almost surely, 2141332011433 is an apocalyptic number.

It is an amenable number.

141332011433 is a deficient number, since it is larger than the sum of its proper divisors (4559097175).

141332011433 is an equidigital number, since it uses as much as digits as its factorization.

141332011433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4559097174.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 141332011433 its reverse (334110233141), we get a palindrome (475442244574).

The spelling of 141332011433 in words is "one hundred forty-one billion, three hundred thirty-two million, eleven thousand, four hundred thirty-three".

Divisors: 1 31 4559097143 141332011433