141333030334042 has 4 divisors (see below), whose sum is σ = 211999545501066. Its totient is φ = 70666515167020.

The previous prime is 141333030333977. The next prime is 141333030334051. The reversal of 141333030334042 is 240433030333141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 117200089158201 + 24132941175841 = 10825899^2 + 4912529^2 .

It is a super-2 number, since 2×141333030334042² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141333030333989 and 141333030334007.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35333257583509 + ... + 35333257583512.

Almost surely, 2^{141333030334042} is an apocalyptic number.

141333030334042 is a deficient number, since it is larger than the sum of its proper divisors (70666515167024).

141333030334042 is an equidigital number, since it uses as much as digits as its factorization.

141333030334042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70666515167023.

The product of its (nonzero) digits is 93312, while the sum is 34.

Adding to 141333030334042 its reverse (240433030333141), we get a palindrome (381766060667183).

Subtracting 141333030334042 from its reverse (240433030333141), we obtain a palindrome (99099999999099).

The spelling of 141333030334042 in words is "one hundred forty-one trillion, three hundred thirty-three billion, thirty million, three hundred thirty-four thousand, forty-two".