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14133323131 = 31345154387
BaseRepresentation
bin11010010100110100…
…10110010101111011
31100110222100012112021
431022122112111323
5212421112320011
610254234055311
71010144156464
oct151232262573
940428305467
1014133323131
115aa298a944
1228a527a537
13144311c0c5
1498109dd6b
1557abbb471
hex34a69657b

14133323131 has 4 divisors (see below), whose sum is σ = 14178477832. Its totient is φ = 14088168432.

The previous prime is 14133323111. The next prime is 14133323161. The reversal of 14133323131 is 13132333141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14133323131 - 27 = 14133323003 is a prime.

It is a super-2 number, since 2×141333231312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14133323096 and 14133323105.

It is not an unprimeable number, because it can be changed into a prime (14133323111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22576881 + ... + 22577506.

It is an arithmetic number, because the mean of its divisors is an integer number (3544619458).

Almost surely, 214133323131 is an apocalyptic number.

14133323131 is a deficient number, since it is larger than the sum of its proper divisors (45154701).

14133323131 is an equidigital number, since it uses as much as digits as its factorization.

14133323131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45154700.

The product of its digits is 1944, while the sum is 25.

Adding to 14133323131 its reverse (13132333141), we get a palindrome (27265656272).

The spelling of 14133323131 in words is "fourteen billion, one hundred thirty-three million, three hundred twenty-three thousand, one hundred thirty-one".

Divisors: 1 313 45154387 14133323131