Base | Representation |
---|---|
bin | 1100110110101110000000… |
… | …1110111101111001000011 |
3 | 1212001012212000020001111101 |
4 | 3031223200032331321003 |
5 | 3323033322313024442 |
6 | 50021055221355231 |
7 | 2656106522212102 |
oct | 315534016757103 |
9 | 55035760201441 |
10 | 14134204423747 |
11 | 455a311a12591 |
12 | 1703378568b17 |
13 | 7b6b07bc2b85 |
14 | 36c1560a2039 |
15 | 1979e2e16cb7 |
hex | cdae03bde43 |
14134204423747 has 2 divisors, whose sum is σ = 14134204423748. Its totient is φ = 14134204423746.
The previous prime is 14134204423721. The next prime is 14134204423763. The reversal of 14134204423747 is 74732440243141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14134204423747 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14134204423697 and 14134204423706.
It is not a weakly prime, because it can be changed into another prime (14134204423777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7067102211873 + 7067102211874.
It is an arithmetic number, because the mean of its divisors is an integer number (7067102211874).
Almost surely, 214134204423747 is an apocalyptic number.
14134204423747 is a deficient number, since it is larger than the sum of its proper divisors (1).
14134204423747 is an equidigital number, since it uses as much as digits as its factorization.
14134204423747 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1806336, while the sum is 46.
Adding to 14134204423747 its reverse (74732440243141), we get a palindrome (88866644666888).
The spelling of 14134204423747 in words is "fourteen trillion, one hundred thirty-four billion, two hundred four million, four hundred twenty-three thousand, seven hundred forty-seven".
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