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1413422000323 = 7127198319349
BaseRepresentation
bin10100100100010110100…
…001000010100011000011
312000010021210212001112221
4110210112201002203003
5141124142013002243
63001152254431511
7204054625526224
oct24442641024303
95003253761487
101413422000323
114a5479964843
121a9b20202597
13a3392550bb8
144c5a502524b
1526b7666dbed
hex149168428c3

1413422000323 has 4 divisors (see below), whose sum is σ = 1413620326800. Its totient is φ = 1413223673848.

The previous prime is 1413422000321. The next prime is 1413422000339. The reversal of 1413422000323 is 3230002243141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413422000323 - 21 = 1413422000321 is a prime.

It is a super-2 number, since 2×14134220003232 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1413422000321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99152548 + ... + 99166801.

It is an arithmetic number, because the mean of its divisors is an integer number (353405081700).

Almost surely, 21413422000323 is an apocalyptic number.

1413422000323 is a deficient number, since it is larger than the sum of its proper divisors (198326477).

1413422000323 is an equidigital number, since it uses as much as digits as its factorization.

1413422000323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 198326476.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 1413422000323 its reverse (3230002243141), we get a palindrome (4643424243464).

The spelling of 1413422000323 in words is "one trillion, four hundred thirteen billion, four hundred twenty-two million, three hundred twenty-three", and thus it is an aban number.

Divisors: 1 7127 198319349 1413422000323