1413510340041 has 12 divisors (see below), whose sum is σ = 2041927421040. Its totient is φ = 942252412920.

The previous prime is 1413510340019. The next prime is 1413510340097. The reversal of 1413510340041 is 1400430153141.

1413510340041 is a `hidden beast` number, since 141 + 3 + 510 + 3 + 4 + 0 + 0 + 4 + 1 = 666.

It is not a de Polignac number, because 1413510340041 - 2¹⁷ = 1413510208969 is a prime.

It is a super-2 number, since 2×1413510340041² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1413510339987 and 1413510340014.

It is not an unprimeable number, because it can be changed into a prime (1413510340141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7215795 + ... + 7409096.

It is an arithmetic number, because the mean of its divisors is an integer number (170160618420).

Almost surely, 2^{1413510340041} is an apocalyptic number.

It is an amenable number.

1413510340041 is a deficient number, since it is larger than the sum of its proper divisors (628417080999).

1413510340041 is a wasteful number, since it uses less digits than its factorization.

1413510340041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14635636 (or 14635633 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 1413510340041 its reverse (1400430153141), we get a palindrome (2813940493182).

The spelling of 1413510340041 in words is "one trillion, four hundred thirteen billion, five hundred ten million, three hundred forty thousand, forty-one".