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14135314153 = 121431164071
BaseRepresentation
bin11010010101000011…
…11100011011101001
31100111010002100200211
431022201330123221
5212422120023103
610254344501121
71010200121302
oct151241743351
940433070624
1014135314153
115aa401a814
1228a5a7a7a1
13144366841c
1498145b7a9
1557ae6136d
hex34a87c6e9

14135314153 has 4 divisors (see below), whose sum is σ = 14136490368. Its totient is φ = 14134137940.

The previous prime is 14135314117. The next prime is 14135314163. The reversal of 14135314153 is 35141353141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14135314153 - 29 = 14135313641 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14135314163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 569893 + ... + 594178.

It is an arithmetic number, because the mean of its divisors is an integer number (3534122592).

Almost surely, 214135314153 is an apocalyptic number.

It is an amenable number.

14135314153 is a deficient number, since it is larger than the sum of its proper divisors (1176215).

14135314153 is a wasteful number, since it uses less digits than its factorization.

14135314153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1176214.

The product of its digits is 10800, while the sum is 31.

Adding to 14135314153 its reverse (35141353141), we get a palindrome (49276667294).

The spelling of 14135314153 in words is "fourteen billion, one hundred thirty-five million, three hundred fourteen thousand, one hundred fifty-three".

Divisors: 1 12143 1164071 14135314153