Base | Representation |
---|---|
bin | 1100110110110100110101… |
… | …0111000100110111110001 |
3 | 1212001101120121021110221221 |
4 | 3031231031113010313301 |
5 | 3323101100012003113 |
6 | 50022001022545041 |
7 | 2656203063133522 |
oct | 315551527046761 |
9 | 55041517243857 |
10 | 14136035266033 |
11 | 456007142248a |
12 | 17037a9738181 |
13 | 7b703a2c13c5 |
14 | 36c28b2c6849 |
15 | 197a9da1398d |
hex | cdb4d5c4df1 |
14136035266033 has 8 divisors (see below), whose sum is σ = 14881173872000. Its totient is φ = 13391010335088.
The previous prime is 14136035266009. The next prime is 14136035266061. The reversal of 14136035266033 is 33066253063141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14136035266033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14136035269033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28163433 + ... + 28660966.
It is an arithmetic number, because the mean of its divisors is an integer number (1860146734000).
Almost surely, 214136035266033 is an apocalyptic number.
It is an amenable number.
14136035266033 is a deficient number, since it is larger than the sum of its proper divisors (745138605967).
14136035266033 is a wasteful number, since it uses less digits than its factorization.
14136035266033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56837511.
The product of its (nonzero) digits is 699840, while the sum is 43.
The spelling of 14136035266033 in words is "fourteen trillion, one hundred thirty-six billion, thirty-five million, two hundred sixty-six thousand, thirty-three".
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