141413201241131 has 4 divisors (see below), whose sum is σ = 141413312786232. Its totient is φ = 141413089696032.

The previous prime is 141413201241127. The next prime is 141413201241167. The reversal of 141413201241131 is 131142102314141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141413201241131 - 2² = 141413201241127 is a prime.

It is a super-2 number, since 2×141413201241131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141413201241094 and 141413201241103.

It is not an unprimeable number, because it can be changed into a prime (141413201241181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53848781 + ... + 56413806.

It is an arithmetic number, because the mean of its divisors is an integer number (35353328196558).

Almost surely, 2^{141413201241131} is an apocalyptic number.

141413201241131 is a deficient number, since it is larger than the sum of its proper divisors (111545101).

141413201241131 is a wasteful number, since it uses less digits than its factorization.

141413201241131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111545100.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 141413201241131 its reverse (131142102314141), we get a palindrome (272555303555272).

The spelling of 141413201241131 in words is "one hundred forty-one trillion, four hundred thirteen billion, two hundred one million, two hundred forty-one thousand, one hundred thirty-one".