1414144441401 has 4 divisors (see below), whose sum is σ = 1885525921872. Its totient is φ = 942762960932.

The previous prime is 1414144441373. The next prime is 1414144441439. The reversal of 1414144441401 is 1041444414141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1414144441401 - 2⁶ = 1414144441337 is a prime.

It is a super-2 number, since 2×1414144441401² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1414144442401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235690740231 + ... + 235690740236.

It is an arithmetic number, because the mean of its divisors is an integer number (471381480468).

Almost surely, 2^{1414144441401} is an apocalyptic number.

It is an amenable number.

1414144441401 is a deficient number, since it is larger than the sum of its proper divisors (471381480471).

1414144441401 is an equidigital number, since it uses as much as digits as its factorization.

1414144441401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 471381480470.

The product of its (nonzero) digits is 16384, while the sum is 33.

Adding to 1414144441401 its reverse (1041444414141), we get a palindrome (2455588855542).

The spelling of 1414144441401 in words is "one trillion, four hundred fourteen billion, one hundred forty-four million, four hundred forty-one thousand, four hundred one".