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1414220131 is a prime number
BaseRepresentation
bin101010001001011…
…0100100101100011
310122120002211022101
41110102310211203
510344020021011
6352155351231
750021446522
oct12422644543
93576084271
101414220131
11666321575
12335752517
13196cba15c
14d5b744b9
15842532c1
hex544b4963

1414220131 has 2 divisors, whose sum is σ = 1414220132. Its totient is φ = 1414220130.

The previous prime is 1414220117. The next prime is 1414220149. The reversal of 1414220131 is 1310224141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1414220131 - 29 = 1414219619 is a prime.

It is a super-2 number, since 2×14142201312 = 4000037157851314322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1414220099 and 1414220108.

It is not a weakly prime, because it can be changed into another prime (1414220161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707110065 + 707110066.

It is an arithmetic number, because the mean of its divisors is an integer number (707110066).

Almost surely, 21414220131 is an apocalyptic number.

1414220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414220131 is an equidigital number, since it uses as much as digits as its factorization.

1414220131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 1414220131 is about 37606.1182655163. The cubic root of 1414220131 is about 1122.4637861476.

Adding to 1414220131 its reverse (1310224141), we get a palindrome (2724444272).

The spelling of 1414220131 in words is "one billion, four hundred fourteen million, two hundred twenty thousand, one hundred thirty-one".