Base | Representation |
---|---|
bin | 11010010101111010… |
… | …00101110001100011 |
3 | 1100111121110220020002 |
4 | 31022331011301203 |
5 | 212430430232212 |
6 | 10255201210215 |
7 | 1010314450145 |
oct | 151275056143 |
9 | 40447426202 |
10 | 14142430307 |
11 | 5aa8040235 |
12 | 28a833096b |
13 | 1444c8a475 |
14 | 982390c95 |
15 | 57b8b9ac2 |
hex | 34af45c63 |
14142430307 has 2 divisors, whose sum is σ = 14142430308. Its totient is φ = 14142430306.
The previous prime is 14142430249. The next prime is 14142430333. The reversal of 14142430307 is 70303424141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14142430307 is a prime.
It is a super-3 number, since 3×141424303073 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 14142430307.
It is not a weakly prime, because it can be changed into another prime (14142430387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7071215153 + 7071215154.
It is an arithmetic number, because the mean of its divisors is an integer number (7071215154).
Almost surely, 214142430307 is an apocalyptic number.
14142430307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14142430307 is an equidigital number, since it uses as much as digits as its factorization.
14142430307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 29.
Adding to 14142430307 its reverse (70303424141), we get a palindrome (84445854448).
The spelling of 14142430307 in words is "fourteen billion, one hundred forty-two million, four hundred thirty thousand, three hundred seven".
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