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14143023411 = 311238961497
BaseRepresentation
bin11010010101111110…
…10110100100110011
31100111122121000210220
431022333112210303
5212431103222121
610255222024123
71010322500256
oct151277264463
940448530726
1014143023411
115aa8405900
1228a8578043
13144513740a
149824a709d
1557b9856c6
hex34afd6933

14143023411 has 12 divisors (see below), whose sum is σ = 20727516936. Its totient is φ = 8571529120.

The previous prime is 14143023379. The next prime is 14143023439. The reversal of 14143023411 is 11432034141.

It is not a de Polignac number, because 14143023411 - 25 = 14143023379 is a prime.

It is a super-2 number, since 2×141430234112 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14143023451) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 19480386 + ... + 19481111.

It is an arithmetic number, because the mean of its divisors is an integer number (1727293078).

Almost surely, 214143023411 is an apocalyptic number.

14143023411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14143023411 is a deficient number, since it is larger than the sum of its proper divisors (6584493525).

14143023411 is a wasteful number, since it uses less digits than its factorization.

14143023411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38961522 (or 38961511 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 14143023411 its reverse (11432034141), we get a palindrome (25575057552).

The spelling of 14143023411 in words is "fourteen billion, one hundred forty-three million, twenty-three thousand, four hundred eleven".

Divisors: 1 3 11 33 121 363 38961497 116884491 428576467 1285729401 4714341137 14143023411