14143100541211 has 2 divisors, whose sum is σ = 14143100541212. Its totient is φ = 14143100541210.

The previous prime is 14143100541187. The next prime is 14143100541233. The reversal of 14143100541211 is 11214500134141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14143100541211 - 2¹³ = 14143100533019 is a prime.

It is a super-2 number, since 2×14143100541211² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14143100541211.

It is not a weakly prime, because it can be changed into another prime (14143100547211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7071550270605 + 7071550270606.

It is an arithmetic number, because the mean of its divisors is an integer number (7071550270606).

Almost surely, 2^{14143100541211} is an apocalyptic number.

14143100541211 is a deficient number, since it is larger than the sum of its proper divisors (1).

14143100541211 is an equidigital number, since it uses as much as digits as its factorization.

14143100541211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 28.

Adding to 14143100541211 its reverse (11214500134141), we get a palindrome (25357600675352).

The spelling of 14143100541211 in words is "fourteen trillion, one hundred forty-three billion, one hundred million, five hundred forty-one thousand, two hundred eleven".