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141431231131 is a prime number
BaseRepresentation
bin1000001110110111110…
…1010101001010011011
3111112001120210221202121
42003231331111022123
54304122343344011
6144550030042111
713134540425551
oct2035575251233
9445046727677
10141431231131
1154a87274293
12234b1049337
131044c256c18
146bb974dbd1
153a2b6d4e71
hex20edf5529b

141431231131 has 2 divisors, whose sum is σ = 141431231132. Its totient is φ = 141431231130.

The previous prime is 141431231083. The next prime is 141431231167. The reversal of 141431231131 is 131132134141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141431231131 - 211 = 141431229083 is a prime.

It is a super-2 number, since 2×1414312311312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141431231096 and 141431231105.

It is not a weakly prime, because it can be changed into another prime (141431231231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70715615565 + 70715615566.

It is an arithmetic number, because the mean of its divisors is an integer number (70715615566).

Almost surely, 2141431231131 is an apocalyptic number.

141431231131 is a deficient number, since it is larger than the sum of its proper divisors (1).

141431231131 is an equidigital number, since it uses as much as digits as its factorization.

141431231131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 864, while the sum is 25.

Adding to 141431231131 its reverse (131132134141), we get a palindrome (272563365272).

The spelling of 141431231131 in words is "one hundred forty-one billion, four hundred thirty-one million, two hundred thirty-one thousand, one hundred thirty-one".