Base | Representation |
---|---|
bin | 100000001010000110000111… |
… | …000000110000011010100011 |
3 | 200112202200202111211222022202 |
4 | 200022012013000300122203 |
5 | 122014202141230244301 |
6 | 1220444341032123415 |
7 | 41535033023621063 |
oct | 4012060700603243 |
9 | 615680674758282 |
10 | 141431243212451 |
11 | 41078720763475 |
12 | 13a423a523656b |
13 | 60bbba812391a |
14 | 26cd4470bd3a3 |
15 | 1153e4049966b |
hex | 80a1870306a3 |
141431243212451 has 4 divisors (see below), whose sum is σ = 146308182633600. Its totient is φ = 136554303791304.
The previous prime is 141431243212397. The next prime is 141431243212463. The reversal of 141431243212451 is 154212342134141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141431243212451 - 218 = 141431242950307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141431243212471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2438469710531 + ... + 2438469710588.
It is an arithmetic number, because the mean of its divisors is an integer number (36577045658400).
Almost surely, 2141431243212451 is an apocalyptic number.
141431243212451 is a deficient number, since it is larger than the sum of its proper divisors (4876939421149).
141431243212451 is an equidigital number, since it uses as much as digits as its factorization.
141431243212451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4876939421148.
The product of its digits is 92160, while the sum is 38.
Adding to 141431243212451 its reverse (154212342134141), we get a palindrome (295643585346592).
The spelling of 141431243212451 in words is "one hundred forty-one trillion, four hundred thirty-one billion, two hundred forty-three million, two hundred twelve thousand, four hundred fifty-one".
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