Search a number
-
+
14143125553 = 18317724263
BaseRepresentation
bin11010010101111111…
…01111100000110001
31100111122210012220221
431022333233200301
5212431120004203
610255224133041
71010323404124
oct151277574061
940448705827
1014143125553
115aa8475617
1228a8607181
131445171a5b
149824d23bb
1557b9a5abd
hex34afef831

14143125553 has 4 divisors (see below), whose sum is σ = 14150851648. Its totient is φ = 14135399460.

The previous prime is 14143125517. The next prime is 14143125559. The reversal of 14143125553 is 35552134141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35552134141 = 39509899849.

It is a cyclic number.

It is not a de Polignac number, because 14143125553 - 213 = 14143117361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14143125559) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3860301 + ... + 3863962.

It is an arithmetic number, because the mean of its divisors is an integer number (3537712912).

Almost surely, 214143125553 is an apocalyptic number.

It is an amenable number.

14143125553 is a deficient number, since it is larger than the sum of its proper divisors (7726095).

14143125553 is an equidigital number, since it uses as much as digits as its factorization.

14143125553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7726094.

The product of its digits is 36000, while the sum is 34.

Adding to 14143125553 its reverse (35552134141), we get a palindrome (49695259694).

The spelling of 14143125553 in words is "fourteen billion, one hundred forty-three million, one hundred twenty-five thousand, five hundred fifty-three".

Divisors: 1 1831 7724263 14143125553