141431324413331 has 4 divisors (see below), whose sum is σ = 141451474203000. Its totient is φ = 141411174623664.

The previous prime is 141431324413271. The next prime is 141431324413343. The reversal of 141431324413331 is 133314423134141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141431324413331 is a prime.

It is a super-2 number, since 2×141431324413331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141431324413361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10074884306 + ... + 10074898343.

It is an arithmetic number, because the mean of its divisors is an integer number (35362868550750).

Almost surely, 2^{141431324413331} is an apocalyptic number.

141431324413331 is a deficient number, since it is larger than the sum of its proper divisors (20149789669).

141431324413331 is an equidigital number, since it uses as much as digits as its factorization.

141431324413331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20149789668.

The product of its digits is 124416, while the sum is 38.

Adding to 141431324413331 its reverse (133314423134141), we get a palindrome (274745747547472).

The spelling of 141431324413331 in words is "one hundred forty-one trillion, four hundred thirty-one billion, three hundred twenty-four million, four hundred thirteen thousand, three hundred thirty-one".