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14143221331 = 83170400257
BaseRepresentation
bin11010010110000000…
…00110111001010011
31100111122222002022021
431023000012321103
5212431131040311
610255230152311
71010324253301
oct151300067123
940448862267
1014143221331
115aa8530578
1228a8652697
1314451a6525
14982519271
1557b9c4171
hex34b006e53

14143221331 has 4 divisors (see below), whose sum is σ = 14313621672. Its totient is φ = 13972820992.

The previous prime is 14143221299. The next prime is 14143221343. The reversal of 14143221331 is 13312234141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14143221331 - 25 = 14143221299 is a prime.

It is a super-2 number, since 2×141432213312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14143221296 and 14143221305.

It is not an unprimeable number, because it can be changed into a prime (14143221931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85200046 + ... + 85200211.

It is an arithmetic number, because the mean of its divisors is an integer number (3578405418).

Almost surely, 214143221331 is an apocalyptic number.

14143221331 is a deficient number, since it is larger than the sum of its proper divisors (170400341).

14143221331 is an equidigital number, since it uses as much as digits as its factorization.

14143221331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170400340.

The product of its digits is 1728, while the sum is 25.

Adding to 14143221331 its reverse (13312234141), we get a palindrome (27455455472).

The spelling of 14143221331 in words is "fourteen billion, one hundred forty-three million, two hundred twenty-one thousand, three hundred thirty-one".

Divisors: 1 83 170400257 14143221331