141433112131 has 4 divisors (see below), whose sum is σ = 141621439264. Its totient is φ = 141244785000.

The previous prime is 141433112113. The next prime is 141433112147. The reversal of 141433112131 is 131211334141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141433112131 - 2¹³ = 141433103939 is a prime.

It is a super-2 number, since 2×141433112131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141433112096 and 141433112105.

It is not an unprimeable number, because it can be changed into a prime (141433112531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94162440 + ... + 94163941.

It is an arithmetic number, because the mean of its divisors is an integer number (35405359816).

Almost surely, 2^141433112131 is an apocalyptic number.

141433112131 is a deficient number, since it is larger than the sum of its proper divisors (188327133).

141433112131 is an equidigital number, since it uses as much as digits as its factorization.

141433112131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188327132.

The product of its digits is 864, while the sum is 25.

Adding to 141433112131 its reverse (131211334141), we get a palindrome (272644446272).

The spelling of 141433112131 in words is "one hundred forty-one billion, four hundred thirty-three million, one hundred twelve thousand, one hundred thirty-one".