Base | Representation |
---|---|
bin | 100000001010001000111110… |
… | …011001111101100011000011 |
3 | 200112202222200221110112110202 |
4 | 200022020332121331203003 |
5 | 122014224441413102441 |
6 | 1220450010223315415 |
7 | 41535202204410035 |
oct | 4012107631754303 |
9 | 615688627415422 |
10 | 141434320050371 |
11 | 41079a5a535327 |
12 | 13a42b0374bb6b |
13 | 60bc2786cc18a |
14 | 26cd6599a7c55 |
15 | 115407066a19b |
hex | 80a23e67d8c3 |
141434320050371 has 2 divisors, whose sum is σ = 141434320050372. Its totient is φ = 141434320050370.
The previous prime is 141434320050341. The next prime is 141434320050407. The reversal of 141434320050371 is 173050023434141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141434320050371 - 214 = 141434320033987 is a prime.
It is a super-2 number, since 2×1414343200503712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (141434320050301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70717160025185 + 70717160025186.
It is an arithmetic number, because the mean of its divisors is an integer number (70717160025186).
Almost surely, 2141434320050371 is an apocalyptic number.
141434320050371 is a deficient number, since it is larger than the sum of its proper divisors (1).
141434320050371 is an equidigital number, since it uses as much as digits as its factorization.
141434320050371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 38.
The spelling of 141434320050371 in words is "one hundred forty-one trillion, four hundred thirty-four billion, three hundred twenty million, fifty thousand, three hundred seventy-one".
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