141434321341121 has 4 divisors (see below), whose sum is σ = 144723491604912. Its totient is φ = 138145151077332.

The previous prime is 141434321341067. The next prime is 141434321341129. The reversal of 141434321341121 is 121143123434141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141434321341121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (141434321341129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1644585131831 + ... + 1644585131916.

It is an arithmetic number, because the mean of its divisors is an integer number (36180872901228).

Almost surely, 2^{141434321341121} is an apocalyptic number.

It is an amenable number.

141434321341121 is a deficient number, since it is larger than the sum of its proper divisors (3289170263791).

141434321341121 is an equidigital number, since it uses as much as digits as its factorization.

141434321341121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3289170263790.

The product of its digits is 27648, while the sum is 35.

Adding to 141434321341121 its reverse (121143123434141), we get a palindrome (262577444775262).

The spelling of 141434321341121 in words is "one hundred forty-one trillion, four hundred thirty-four billion, three hundred twenty-one million, three hundred forty-one thousand, one hundred twenty-one".