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14144212241 = 31456264911
BaseRepresentation
bin11010010110000111…
…11000110100010001
31100111201211102120122
431023003320310101
5212431404242431
610255303320025
71010335551245
oct151303706421
940451742518
1014144212241
115aa9048005
1228a8a50015
131445462573
149826d6425
1557bb1ca7b
hex34b0f8d11

14144212241 has 4 divisors (see below), whose sum is σ = 14600477184. Its totient is φ = 13687947300.

The previous prime is 14144212217. The next prime is 14144212337. The reversal of 14144212241 is 14221244141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14144212241 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14144212241.

It is not an unprimeable number, because it can be changed into a prime (14144212141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 228132425 + ... + 228132486.

It is an arithmetic number, because the mean of its divisors is an integer number (3650119296).

Almost surely, 214144212241 is an apocalyptic number.

It is an amenable number.

14144212241 is a deficient number, since it is larger than the sum of its proper divisors (456264943).

14144212241 is an equidigital number, since it uses as much as digits as its factorization.

14144212241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 456264942.

The product of its digits is 2048, while the sum is 26.

Adding to 14144212241 its reverse (14221244141), we get a palindrome (28365456382).

The spelling of 14144212241 in words is "fourteen billion, one hundred forty-four million, two hundred twelve thousand, two hundred forty-one".

Divisors: 1 31 456264911 14144212241