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141442500133403 = 729696761084401
BaseRepresentation
bin100000001010010000100101…
…111110100000001000011011
3200112210202211000201210211222
4200022100211332200020123
5122014343220013232103
61220453442035042255
741535612003102440
oct4012204576401033
9615722730653758
10141442500133403
1141082477a21827
1213a4460714038b
1360bcc80344bb1
1426cdbd414b9c7
15115439d888638
hex80a425fa021b

141442500133403 has 8 divisors (see below), whose sum is σ = 167222660256480. Its totient is φ = 117055862179200.

The previous prime is 141442500133397. The next prime is 141442500133411. The reversal of 141442500133403 is 304331005244141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 141442500133403 - 28 = 141442500133147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141442500135403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 348380541998 + ... + 348380542403.

It is an arithmetic number, because the mean of its divisors is an integer number (20902832532060).

Almost surely, 2141442500133403 is an apocalyptic number.

141442500133403 is a deficient number, since it is larger than the sum of its proper divisors (25780160123077).

141442500133403 is an equidigital number, since it uses as much as digits as its factorization.

141442500133403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 696761084437.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 141442500133403 its reverse (304331005244141), we get a palindrome (445773505377544).

The spelling of 141442500133403 in words is "one hundred forty-one trillion, four hundred forty-two billion, five hundred million, one hundred thirty-three thousand, four hundred three".

Divisors: 1 7 29 203 696761084401 4877327590807 20206071447629 141442500133403