Base | Representation |
---|---|
bin | 10100100101011101100… |
… | …100111101101000110001 |
3 | 12000020100220012122022102 |
4 | 110211131210331220301 |
5 | 141134112214223441 |
6 | 3001510443550145 |
7 | 204126313253366 |
oct | 24453544755061 |
9 | 5006326178272 |
10 | 1414614211121 |
11 | 4a5a30930421 |
12 | 1aa1b352b355 |
13 | a3522548b87 |
14 | 4c6794c846d |
15 | 26be616b69b |
hex | 1495d93da31 |
1414614211121 has 2 divisors, whose sum is σ = 1414614211122. Its totient is φ = 1414614211120.
The previous prime is 1414614211069. The next prime is 1414614211139. The reversal of 1414614211121 is 1211124164141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1354570099600 + 60044111521 = 1163860^2 + 245039^2 .
It is a cyclic number.
It is not a de Polignac number, because 1414614211121 - 218 = 1414613948977 is a prime.
It is a super-2 number, since 2×14146142111212 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1414614111121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707307105560 + 707307105561.
It is an arithmetic number, because the mean of its divisors is an integer number (707307105561).
Almost surely, 21414614211121 is an apocalyptic number.
It is an amenable number.
1414614211121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414614211121 is an equidigital number, since it uses as much as digits as its factorization.
1414614211121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1536, while the sum is 29.
Adding to 1414614211121 its reverse (1211124164141), we get a palindrome (2625738375262).
The spelling of 1414614211121 in words is "one trillion, four hundred fourteen billion, six hundred fourteen million, two hundred eleven thousand, one hundred twenty-one".
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