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14148577 is a prime number
BaseRepresentation
bin110101111110…
…001111100001
3222121211012101
4311332033201
512110223302
61223130401
7231155332
oct65761741
928554171
1014148577
117a94043
1248a3a01
132c14c51
141c44289
151397287
hexd7e3e1

14148577 has 2 divisors, whose sum is σ = 14148578. Its totient is φ = 14148576.

The previous prime is 14148569. The next prime is 14148581. The reversal of 14148577 is 77584141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14130081 + 18496 = 3759^2 + 136^2 .

It is a cyclic number.

It is not a de Polignac number, because 14148577 - 23 = 14148569 is a prime.

It is a super-3 number, since 3×141485773 (a number of 22 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14148557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7074288 + 7074289.

It is an arithmetic number, because the mean of its divisors is an integer number (7074289).

Almost surely, 214148577 is an apocalyptic number.

It is an amenable number.

14148577 is a deficient number, since it is larger than the sum of its proper divisors (1).

14148577 is an equidigital number, since it uses as much as digits as its factorization.

14148577 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31360, while the sum is 37.

The square root of 14148577 is about 3761.4594242129. The cubic root of 14148577 is about 241.8638272676.

Subtracting from 14148577 its sum of digits (37), we obtain a triangular number (14148540 = T5319).

The spelling of 14148577 in words is "fourteen million, one hundred forty-eight thousand, five hundred seventy-seven".