Base | Representation |
---|---|
bin | 1000001111000110110… |
… | …1111000111000000011 |
3 | 111112012222110202222021 |
4 | 2003301231320320003 |
5 | 4304240014320341 |
6 | 145000201422311 |
7 | 13136234431444 |
oct | 2036155707003 |
9 | 445188422867 |
10 | 141494291971 |
11 | 5500992588a |
12 | 2350a19a997 |
13 | 1045c336126 |
14 | 6bc3c872cb |
15 | 3a31ede9d1 |
hex | 20f1b78e03 |
141494291971 has 2 divisors, whose sum is σ = 141494291972. Its totient is φ = 141494291970.
The previous prime is 141494291963. The next prime is 141494292011. The reversal of 141494291971 is 179192494141.
It is a weak prime.
It is an emirp because it is prime and its reverse (179192494141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141494291971 - 23 = 141494291963 is a prime.
It is not a weakly prime, because it can be changed into another prime (141494291371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70747145985 + 70747145986.
It is an arithmetic number, because the mean of its divisors is an integer number (70747145986).
Almost surely, 2141494291971 is an apocalyptic number.
141494291971 is a deficient number, since it is larger than the sum of its proper divisors (1).
141494291971 is an equidigital number, since it uses as much as digits as its factorization.
141494291971 is an evil number, because the sum of its binary digits is even.
The product of its digits is 653184, while the sum is 52.
The spelling of 141494291971 in words is "one hundred forty-one billion, four hundred ninety-four million, two hundred ninety-one thousand, nine hundred seventy-one".
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