14150003411353 has 4 divisors (see below), whose sum is σ = 14150548695808. Its totient is φ = 14149458126900.

The previous prime is 14150003411231. The next prime is 14150003411359. The reversal of 14150003411353 is 35311430005141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14150003411353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14150003411359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272603301 + ... + 272655202.

It is an arithmetic number, because the mean of its divisors is an integer number (3537637173952).

Almost surely, 2^{14150003411353} is an apocalyptic number.

It is an amenable number.

14150003411353 is a deficient number, since it is larger than the sum of its proper divisors (545284455).

14150003411353 is an equidigital number, since it uses as much as digits as its factorization.

14150003411353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 545284454.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 14150003411353 its reverse (35311430005141), we get a palindrome (49461433416494).

The spelling of 14150003411353 in words is "fourteen trillion, one hundred fifty billion, three million, four hundred eleven thousand, three hundred fifty-three".