Base | Representation |
---|---|
bin | 10100100101111101100… |
… | …111000110000110110011 |
3 | 12000021202100110220112011 |
4 | 110211331213012012303 |
5 | 141141212310003021 |
6 | 3002040042543351 |
7 | 204145530322363 |
oct | 24457547060663 |
9 | 5007670426464 |
10 | 1415151641011 |
11 | 4a6187232459 |
12 | 1aa323507b57 |
13 | a35a99a7a24 |
14 | 4c6caa249a3 |
15 | 26c28429de1 |
hex | 1497d9c61b3 |
1415151641011 has 2 divisors, whose sum is σ = 1415151641012. Its totient is φ = 1415151641010.
The previous prime is 1415151640943. The next prime is 1415151641017. The reversal of 1415151641011 is 1101461515141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1415151641011 - 211 = 1415151638963 is a prime.
It is a super-2 number, since 2×14151516410112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1415151641017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707575820505 + 707575820506.
It is an arithmetic number, because the mean of its divisors is an integer number (707575820506).
Almost surely, 21415151641011 is an apocalyptic number.
1415151641011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1415151641011 is an equidigital number, since it uses as much as digits as its factorization.
1415151641011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 31.
The spelling of 1415151641011 in words is "one trillion, four hundred fifteen billion, one hundred fifty-one million, six hundred forty-one thousand, eleven".
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