Base | Representation |
---|---|
bin | 1000001111010010001… |
… | …0000001001111000011 |
3 | 111112100021022210212002 |
4 | 2003310202001033003 |
5 | 4304334111342011 |
6 | 145005005454215 |
7 | 13140350000525 |
oct | 2036442011703 |
9 | 445307283762 |
10 | 141541512131 |
11 | 55033548008 |
12 | 23521b7136b |
13 | 1046905a156 |
14 | 6bca259a15 |
15 | 3a3621ac3b |
hex | 20f48813c3 |
141541512131 has 2 divisors, whose sum is σ = 141541512132. Its totient is φ = 141541512130.
The previous prime is 141541512107. The next prime is 141541512191. The reversal of 141541512131 is 131215145141.
It is a weak prime.
It is an emirp because it is prime and its reverse (131215145141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141541512131 is a prime.
It is a super-2 number, since 2×1415415121312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 141541512094 and 141541512103.
It is not a weakly prime, because it can be changed into another prime (141541512191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70770756065 + 70770756066.
It is an arithmetic number, because the mean of its divisors is an integer number (70770756066).
Almost surely, 2141541512131 is an apocalyptic number.
141541512131 is a deficient number, since it is larger than the sum of its proper divisors (1).
141541512131 is an equidigital number, since it uses as much as digits as its factorization.
141541512131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2400, while the sum is 29.
Adding to 141541512131 its reverse (131215145141), we get a palindrome (272756657272).
The spelling of 141541512131 in words is "one hundred forty-one billion, five hundred forty-one million, five hundred twelve thousand, one hundred thirty-one".
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