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141550132121 is a prime number
BaseRepresentation
bin1000001111010100001…
…0111001101110011001
3111112100212112202020222
42003311002321232121
54304343313211441
6145005514325425
713140513161636
oct2036502715631
9445325482228
10141550132121
11550383a5372
1223524a29875
131046aa87838
146bcb46118d
153a36d6ed4b
hex20f50b9b99

141550132121 has 2 divisors, whose sum is σ = 141550132122. Its totient is φ = 141550132120.

The previous prime is 141550132051. The next prime is 141550132151. The reversal of 141550132121 is 121231055141.

141550132121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140577004096 + 973128025 = 374936^2 + 31195^2 .

It is a cyclic number.

It is not a de Polignac number, because 141550132121 - 222 = 141545937817 is a prime.

It is not a weakly prime, because it can be changed into another prime (141550132151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70775066060 + 70775066061.

It is an arithmetic number, because the mean of its divisors is an integer number (70775066061).

Almost surely, 2141550132121 is an apocalyptic number.

It is an amenable number.

141550132121 is a deficient number, since it is larger than the sum of its proper divisors (1).

141550132121 is an equidigital number, since it uses as much as digits as its factorization.

141550132121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 141550132121 its reverse (121231055141), we get a palindrome (262781187262).

The spelling of 141550132121 in words is "one hundred forty-one billion, five hundred fifty million, one hundred thirty-two thousand, one hundred twenty-one".