Base | Representation |
---|---|
bin | 11010010111011110… |
… | …10111110111111001 |
3 | 1100112112021120121122 |
4 | 31023233113313321 |
5 | 212442314033031 |
6 | 10300351515025 |
7 | 1010534466533 |
oct | 151357276771 |
9 | 40475246548 |
10 | 14155611641 |
11 | 60045235a6 |
12 | 28b0828a75 |
13 | 1447924082 |
14 | 984022853 |
15 | 57cb2047b |
hex | 34bbd7df9 |
14155611641 has 2 divisors, whose sum is σ = 14155611642. Its totient is φ = 14155611640.
The previous prime is 14155611637. The next prime is 14155611647. The reversal of 14155611641 is 14611655141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9760452025 + 4395159616 = 98795^2 + 66296^2 .
It is an emirp because it is prime and its reverse (14611655141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14155611641 - 22 = 14155611637 is a prime.
It is a super-4 number, since 4×141556116414 (a number of 42 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (14155611647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7077805820 + 7077805821.
It is an arithmetic number, because the mean of its divisors is an integer number (7077805821).
Almost surely, 214155611641 is an apocalyptic number.
It is an amenable number.
14155611641 is a deficient number, since it is larger than the sum of its proper divisors (1).
14155611641 is an equidigital number, since it uses as much as digits as its factorization.
14155611641 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 35.
The spelling of 14155611641 in words is "fourteen billion, one hundred fifty-five million, six hundred eleven thousand, six hundred forty-one".
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