Base | Representation |
---|---|
bin | 100000001100101110011111… |
… | …101101100111111111010001 |
3 | 200120101222102222200010112020 |
4 | 200030232133231213333101 |
5 | 122030132432320112113 |
6 | 1221103402000522053 |
7 | 41554063343253225 |
oct | 4014563755477721 |
9 | 616358388603466 |
10 | 141612046254033 |
11 | 41138371323683 |
12 | 13a71443920329 |
13 | 6102c602445b4 |
14 | 26d80b97d6785 |
15 | 11589c342b023 |
hex | 80cb9fb67fd1 |
141612046254033 has 4 divisors (see below), whose sum is σ = 188816061672048. Its totient is φ = 94408030836020.
The previous prime is 141612046253987. The next prime is 141612046254059. The reversal of 141612046254033 is 330452640216141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 141612046254033 - 213 = 141612046245841 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141612046254073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23602007709003 + ... + 23602007709008.
It is an arithmetic number, because the mean of its divisors is an integer number (47204015418012).
Almost surely, 2141612046254033 is an apocalyptic number.
It is an amenable number.
141612046254033 is a deficient number, since it is larger than the sum of its proper divisors (47204015418015).
141612046254033 is an equidigital number, since it uses as much as digits as its factorization.
141612046254033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47204015418014.
The product of its (nonzero) digits is 414720, while the sum is 42.
The spelling of 141612046254033 in words is "one hundred forty-one trillion, six hundred twelve billion, forty-six million, two hundred fifty-four thousand, thirty-three".
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