Base | Representation |
---|---|
bin | 10100100111001010110… |
… | …010010010111001001011 |
3 | 12000102002120211121221221 |
4 | 110213022302102321023 |
5 | 141201340241010403 |
6 | 3002412334342511 |
7 | 204222601640002 |
oct | 24471262227113 |
9 | 5012076747857 |
10 | 1416446422603 |
11 | 4a6791095a93 |
12 | 1aa62505aa37 |
13 | a3755006694 |
14 | 4c7b0987c39 |
15 | 26ca1e38dbd |
hex | 149cac92e4b |
1416446422603 has 4 divisors (see below), whose sum is σ = 1416454511128. Its totient is φ = 1416438334080.
The previous prime is 1416446422493. The next prime is 1416446422621. The reversal of 1416446422603 is 3062246446141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1416446422603 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1416446422603.
It is not an unprimeable number, because it can be changed into a prime (1416446422693) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3775638 + ... + 4133803.
It is an arithmetic number, because the mean of its divisors is an integer number (354113627782).
Almost surely, 21416446422603 is an apocalyptic number.
1416446422603 is a deficient number, since it is larger than the sum of its proper divisors (8088525).
1416446422603 is an equidigital number, since it uses as much as digits as its factorization.
1416446422603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8088524.
The product of its (nonzero) digits is 663552, while the sum is 43.
The spelling of 1416446422603 in words is "one trillion, four hundred sixteen billion, four hundred forty-six million, four hundred twenty-two thousand, six hundred three".
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