Base | Representation |
---|---|
bin | 1100111000101101101010… |
… | …1001100111001001110011 |
3 | 1212011111022001212020210012 |
4 | 3032023122221213021303 |
5 | 3324114011420433241 |
6 | 50044523330125135 |
7 | 2661431623005125 |
oct | 316133251471163 |
9 | 55144261766705 |
10 | 14168470483571 |
11 | 45728a6242498 |
12 | 1709b401207ab |
13 | 7ba109052c11 |
14 | 36da86d1b215 |
15 | 19884b31d6eb |
hex | ce2daa67273 |
14168470483571 has 2 divisors, whose sum is σ = 14168470483572. Its totient is φ = 14168470483570.
The previous prime is 14168470483487. The next prime is 14168470483591. The reversal of 14168470483571 is 17538407486141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14168470483571 - 214 = 14168470467187 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14168470483571.
It is not a weakly prime, because it can be changed into another prime (14168470483591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7084235241785 + 7084235241786.
It is an arithmetic number, because the mean of its divisors is an integer number (7084235241786).
Almost surely, 214168470483571 is an apocalyptic number.
14168470483571 is a deficient number, since it is larger than the sum of its proper divisors (1).
14168470483571 is an equidigital number, since it uses as much as digits as its factorization.
14168470483571 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18063360, while the sum is 59.
The spelling of 14168470483571 in words is "fourteen trillion, one hundred sixty-eight billion, four hundred seventy million, four hundred eighty-three thousand, five hundred seventy-one".
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