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14181441 = 34727147
BaseRepresentation
bin110110000110…
…010001000001
3222200111021120
4312012101001
512112301231
61223542453
7231353211
oct66062101
928614246
1014181441
1180067aa
1248baa29
132c26bb1
141c52241
1513a1d96
hexd86441

14181441 has 4 divisors (see below), whose sum is σ = 18908592. Its totient is φ = 9454292.

The previous prime is 14181437. The next prime is 14181481. The reversal of 14181441 is 14418141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14181441 - 22 = 14181437 is a prime.

It is a super-2 number, since 2×141814412 = 402226537672962, which contains 22 as substring.

It is a Curzon number.

It is a nialpdrome in base 16.

It is not an unprimeable number, because it can be changed into a prime (14181481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2363571 + ... + 2363576.

It is an arithmetic number, because the mean of its divisors is an integer number (4727148).

Almost surely, 214181441 is an apocalyptic number.

It is an amenable number.

14181441 is a deficient number, since it is larger than the sum of its proper divisors (4727151).

14181441 is an equidigital number, since it uses as much as digits as its factorization.

14181441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4727150.

The product of its digits is 512, while the sum is 24.

The square root of 14181441 is about 3765.8254075302. The cubic root of 14181441 is about 242.0509477689.

Adding to 14181441 its reverse (14418141), we get a palindrome (28599582).

The spelling of 14181441 in words is "fourteen million, one hundred eighty-one thousand, four hundred forty-one".

Divisors: 1 3 4727147 14181441