Base | Representation |
---|---|
bin | 11010011010100100… |
… | …10101110010100001 |
3 | 1100121100002122201011 |
4 | 31031102111302201 |
5 | 213020434232421 |
6 | 10303115540521 |
7 | 1011301142311 |
oct | 151522256241 |
9 | 40540078634 |
10 | 14181555361 |
11 | 6018133496 |
12 | 28b945a741 |
13 | 145010899c |
14 | 987657441 |
15 | 5800474e1 |
hex | 34d495ca1 |
14181555361 has 6 divisors (see below), whose sum is σ = 14363347362. Its totient is φ = 14002035840.
The previous prime is 14181555343. The next prime is 14181555383. The reversal of 14181555361 is 16355518141.
It can be written as a sum of positive squares in only one way, i.e., 7483115025 + 6698440336 = 86505^2 + 81844^2 .
It is not a de Polignac number, because 14181555361 - 27 = 14181555233 is a prime.
It is a super-2 number, since 2×141815553612 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14181555061) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1129920 + ... + 1142401.
It is an arithmetic number, because the mean of its divisors is an integer number (2393891227).
Almost surely, 214181555361 is an apocalyptic number.
It is an amenable number.
14181555361 is a deficient number, since it is larger than the sum of its proper divisors (181792001).
14181555361 is an frugal number, since it uses more digits than its factorization.
14181555361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2272479 (or 2272400 counting only the distinct ones).
The product of its digits is 72000, while the sum is 40.
The spelling of 14181555361 in words is "fourteen billion, one hundred eighty-one million, five hundred fifty-five thousand, three hundred sixty-one".
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