Base | Representation |
---|---|
bin | 10100101001011111111… |
… | …010011011101011111001 |
3 | 12000122112221200021011021 |
4 | 110221133322123223321 |
5 | 141222001240022303 |
6 | 3003504511502441 |
7 | 204341602030624 |
oct | 24513772335371 |
9 | 5018487607137 |
10 | 1418948360953 |
11 | 4a78553a3332 |
12 | 1ab002b27a21 |
13 | a3a63464186 |
14 | 4c96ad80dbb |
15 | 26d9b8e8ebd |
hex | 14a5fe9baf9 |
1418948360953 has 2 divisors, whose sum is σ = 1418948360954. Its totient is φ = 1418948360952.
The previous prime is 1418948360923. The next prime is 1418948360981. The reversal of 1418948360953 is 3590638498141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1418509584144 + 438776809 = 1191012^2 + 20947^2 .
It is a cyclic number.
It is not a de Polignac number, because 1418948360953 - 29 = 1418948360441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1418948360891 and 1418948360900.
It is not a weakly prime, because it can be changed into another prime (1418948360923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 709474180476 + 709474180477.
It is an arithmetic number, because the mean of its divisors is an integer number (709474180477).
Almost surely, 21418948360953 is an apocalyptic number.
It is an amenable number.
1418948360953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1418948360953 is an equidigital number, since it uses as much as digits as its factorization.
1418948360953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22394880, while the sum is 61.
The spelling of 1418948360953 in words is "one trillion, four hundred eighteen billion, nine hundred forty-eight million, three hundred sixty thousand, nine hundred fifty-three".
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