14189953353 has 4 divisors (see below), whose sum is σ = 18919937808. Its totient is φ = 9459968900.

The previous prime is 14189953333. The next prime is 14189953367. The reversal of 14189953353 is 35335998141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35335998141 = 3 ⋅11778666047.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14189953353 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14189953296 and 14189953305.

It is not an unprimeable number, because it can be changed into a prime (14189953333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2364992223 + ... + 2364992228.

It is an arithmetic number, because the mean of its divisors is an integer number (4729984452).

Almost surely, 2^14189953353 is an apocalyptic number.

It is an amenable number.

14189953353 is a deficient number, since it is larger than the sum of its proper divisors (4729984455).

14189953353 is an equidigital number, since it uses as much as digits as its factorization.

14189953353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4729984454.

The product of its digits is 1749600, while the sum is 51.

The spelling of 14189953353 in words is "fourteen billion, one hundred eighty-nine million, nine hundred fifty-three thousand, three hundred fifty-three".