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142001268553 is a prime number
BaseRepresentation
bin1000010000111111101…
…1110110011101001001
3111120112022102212002201
42010033323312131021
54311304311043203
6145122352000201
713154631603334
oct2041773663511
9446468385081
10142001268553
115524a0178a1
122362bb30061
1310510391881
146c3133761b
153a61784e1d
hex210fef6749

142001268553 has 2 divisors, whose sum is σ = 142001268554. Its totient is φ = 142001268552.

The previous prime is 142001268527. The next prime is 142001268571. The reversal of 142001268553 is 355862100241.

Adding to 142001268553 its reverse (355862100241), we get a palindrome (497863368794).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77524378624 + 64476889929 = 278432^2 + 253923^2 .

It is a cyclic number.

It is not a de Polignac number, because 142001268553 - 233 = 133411333961 is a prime.

It is a super-2 number, since 2×1420012685532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (142001268593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71000634276 + 71000634277.

It is an arithmetic number, because the mean of its divisors is an integer number (71000634277).

Almost surely, 2142001268553 is an apocalyptic number.

It is an amenable number.

142001268553 is a deficient number, since it is larger than the sum of its proper divisors (1).

142001268553 is an equidigital number, since it uses as much as digits as its factorization.

142001268553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 37.

The spelling of 142001268553 in words is "one hundred forty-two billion, one million, two hundred sixty-eight thousand, five hundred fifty-three".