Base | Representation |
---|---|
bin | 1000010000111111101… |
… | …1110110011101001001 |
3 | 111120112022102212002201 |
4 | 2010033323312131021 |
5 | 4311304311043203 |
6 | 145122352000201 |
7 | 13154631603334 |
oct | 2041773663511 |
9 | 446468385081 |
10 | 142001268553 |
11 | 5524a0178a1 |
12 | 2362bb30061 |
13 | 10510391881 |
14 | 6c3133761b |
15 | 3a61784e1d |
hex | 210fef6749 |
142001268553 has 2 divisors, whose sum is σ = 142001268554. Its totient is φ = 142001268552.
The previous prime is 142001268527. The next prime is 142001268571. The reversal of 142001268553 is 355862100241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77524378624 + 64476889929 = 278432^2 + 253923^2 .
It is a cyclic number.
It is not a de Polignac number, because 142001268553 - 233 = 133411333961 is a prime.
It is a super-2 number, since 2×1420012685532 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142001268593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71000634276 + 71000634277.
It is an arithmetic number, because the mean of its divisors is an integer number (71000634277).
Almost surely, 2142001268553 is an apocalyptic number.
It is an amenable number.
142001268553 is a deficient number, since it is larger than the sum of its proper divisors (1).
142001268553 is an equidigital number, since it uses as much as digits as its factorization.
142001268553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 142001268553 its reverse (355862100241), we get a palindrome (497863368794).
The spelling of 142001268553 in words is "one hundred forty-two billion, one million, two hundred sixty-eight thousand, five hundred fifty-three".
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