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1420110542353 is a prime number
BaseRepresentation
bin10100101010100101001…
…011110011011000010001
312000202112221112012022211
4110222211023303120101
5141231341244323403
63004220105232121
7204412443304606
oct24524513633021
95022487465284
101420110542353
114a82a1419428
121ab288192641
13a3bba176989
144ca3b4686ad
1526e1896406d
hex14aa52f3611

1420110542353 has 2 divisors, whose sum is σ = 1420110542354. Its totient is φ = 1420110542352.

The previous prime is 1420110542341. The next prime is 1420110542453. The reversal of 1420110542353 is 3532450110241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 862507836369 + 557602705984 = 928713^2 + 746728^2 .

It is a cyclic number.

It is not a de Polignac number, because 1420110542353 - 217 = 1420110411281 is a prime.

It is not a weakly prime, because it can be changed into another prime (1420110542303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710055271176 + 710055271177.

It is an arithmetic number, because the mean of its divisors is an integer number (710055271177).

Almost surely, 21420110542353 is an apocalyptic number.

It is an amenable number.

1420110542353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420110542353 is an equidigital number, since it uses as much as digits as its factorization.

1420110542353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1420110542353 its reverse (3532450110241), we get a palindrome (4952560652594).

The spelling of 1420110542353 in words is "one trillion, four hundred twenty billion, one hundred ten million, five hundred forty-two thousand, three hundred fifty-three".