1420122154411 has 4 divisors (see below), whose sum is σ = 1422912178800. Its totient is φ = 1417332130024.

The previous prime is 1420122154393. The next prime is 1420122154441. The reversal of 1420122154411 is 1144512210241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1420122154411 - 2¹⁷ = 1420122023339 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1420122154411.

It is not an unprimeable number, because it can be changed into a prime (1420122154441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1395011431 + ... + 1395012448.

It is an arithmetic number, because the mean of its divisors is an integer number (355728044700).

Almost surely, 2^{1420122154411} is an apocalyptic number.

1420122154411 is a deficient number, since it is larger than the sum of its proper divisors (2790024389).

1420122154411 is an equidigital number, since it uses as much as digits as its factorization.

1420122154411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2790024388.

The product of its (nonzero) digits is 2560, while the sum is 28.

Adding to 1420122154411 its reverse (1144512210241), we get a palindrome (2564634364652).

The spelling of 1420122154411 in words is "one trillion, four hundred twenty billion, one hundred twenty-two million, one hundred fifty-four thousand, four hundred eleven".