Base | Representation |
---|---|
bin | 10100101010100101111… |
… | …011101101101111110001 |
3 | 12000202120211011022012002 |
4 | 110222211323231233301 |
5 | 141231403003232233 |
6 | 3004221234343345 |
7 | 204412655125325 |
oct | 24524573555761 |
9 | 5022524138162 |
10 | 1420123102193 |
11 | 4a82a8517864 |
12 | 1ab29042ab55 |
13 | a3bbc953733 |
14 | 4ca3cdb7985 |
15 | 26e19ae56e8 |
hex | 14aa5eedbf1 |
1420123102193 has 2 divisors, whose sum is σ = 1420123102194. Its totient is φ = 1420123102192.
The previous prime is 1420123102187. The next prime is 1420123102267. The reversal of 1420123102193 is 3912013210241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1400205989809 + 19917112384 = 1183303^2 + 141128^2 .
It is a cyclic number.
It is not a de Polignac number, because 1420123102193 - 214 = 1420123085809 is a prime.
It is a super-3 number, since 3×14201231021933 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1420123102103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710061551096 + 710061551097.
It is an arithmetic number, because the mean of its divisors is an integer number (710061551097).
Almost surely, 21420123102193 is an apocalyptic number.
It is an amenable number.
1420123102193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420123102193 is an equidigital number, since it uses as much as digits as its factorization.
1420123102193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 1420123102193 in words is "one trillion, four hundred twenty billion, one hundred twenty-three million, one hundred two thousand, one hundred ninety-three".
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