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14201241 = 35980233
BaseRepresentation
bin110110001011…
…000110011001
3222201111102220
4312023012121
512113414431
61224214253
7231465015
oct66130631
928644386
1014201241
11801a66a
12490a389
132c32c02
141c59545
1513a7b96
hexd8b199

14201241 has 8 divisors (see below), whose sum is σ = 19256160. Its totient is φ = 9306912.

The previous prime is 14201233. The next prime is 14201263. The reversal of 14201241 is 14210241.

14201241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14201241 - 23 = 14201233 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 14201241.

It is not an unprimeable number, because it can be changed into a prime (14201221) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39940 + ... + 40293.

It is an arithmetic number, because the mean of its divisors is an integer number (2407020).

Almost surely, 214201241 is an apocalyptic number.

It is an amenable number.

14201241 is a deficient number, since it is larger than the sum of its proper divisors (5054919).

14201241 is an equidigital number, since it uses as much as digits as its factorization.

14201241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80295.

The product of its (nonzero) digits is 64, while the sum is 15.

The square root of 14201241 is about 3768.4533962887. The cubic root of 14201241 is about 242.1635451659.

Adding to 14201241 its reverse (14210241), we get a palindrome (28411482).

The spelling of 14201241 in words is "fourteen million, two hundred one thousand, two hundred forty-one".

Divisors: 1 3 59 177 80233 240699 4733747 14201241