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1420132572689 is a prime number
BaseRepresentation
bin10100101010100110011…
…111110101111000010001
312000202121110222110021012
4110222212133311320101
5141231412414311224
63004222213340305
7204413131461155
oct24524637657021
95022543873235
101420132572689
114a83028a6116
121ab293637695
13a3bc18bb28c
144ca40361065
1526e1a86680e
hex14aa67f5e11

1420132572689 has 2 divisors, whose sum is σ = 1420132572690. Its totient is φ = 1420132572688.

The previous prime is 1420132572637. The next prime is 1420132572709. The reversal of 1420132572689 is 9862752310241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 914280192400 + 505852380289 = 956180^2 + 711233^2 .

It is a cyclic number.

It is not a de Polignac number, because 1420132572689 - 224 = 1420115795473 is a prime.

It is not a weakly prime, because it can be changed into another prime (1420132572589) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710066286344 + 710066286345.

It is an arithmetic number, because the mean of its divisors is an integer number (710066286345).

It is a 1-persistent number, because it is pandigital, but 2⋅1420132572689 = 2840265145378 is not.

Almost surely, 21420132572689 is an apocalyptic number.

It is an amenable number.

1420132572689 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420132572689 is an equidigital number, since it uses as much as digits as its factorization.

1420132572689 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 1420132572689 in words is "one trillion, four hundred twenty billion, one hundred thirty-two million, five hundred seventy-two thousand, six hundred eighty-nine".