Base | Representation |
---|---|
bin | 10100101010100110011… |
… | …111110101111000010001 |
3 | 12000202121110222110021012 |
4 | 110222212133311320101 |
5 | 141231412414311224 |
6 | 3004222213340305 |
7 | 204413131461155 |
oct | 24524637657021 |
9 | 5022543873235 |
10 | 1420132572689 |
11 | 4a83028a6116 |
12 | 1ab293637695 |
13 | a3bc18bb28c |
14 | 4ca40361065 |
15 | 26e1a86680e |
hex | 14aa67f5e11 |
1420132572689 has 2 divisors, whose sum is σ = 1420132572690. Its totient is φ = 1420132572688.
The previous prime is 1420132572637. The next prime is 1420132572709. The reversal of 1420132572689 is 9862752310241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 914280192400 + 505852380289 = 956180^2 + 711233^2 .
It is a cyclic number.
It is not a de Polignac number, because 1420132572689 - 224 = 1420115795473 is a prime.
It is not a weakly prime, because it can be changed into another prime (1420132572589) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710066286344 + 710066286345.
It is an arithmetic number, because the mean of its divisors is an integer number (710066286345).
It is a 1-persistent number, because it is pandigital, but 2⋅1420132572689 = 2840265145378 is not.
Almost surely, 21420132572689 is an apocalyptic number.
It is an amenable number.
1420132572689 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420132572689 is an equidigital number, since it uses as much as digits as its factorization.
1420132572689 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 50.
The spelling of 1420132572689 in words is "one trillion, four hundred twenty billion, one hundred thirty-two million, five hundred seventy-two thousand, six hundred eighty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •