Base | Representation |
---|---|
bin | 10100101010100110100… |
… | …110100000110110010011 |
3 | 12000202121121021022021000 |
4 | 110222212212200312103 |
5 | 141231413341242210 |
6 | 3004222315033043 |
7 | 204413152363665 |
oct | 24524646406623 |
9 | 5022547238230 |
10 | 1420134321555 |
11 | 4a8303890064 |
12 | 1ab29413b783 |
13 | a3bc2081301 |
14 | 4ca40698535 |
15 | 26e1aaaeac0 |
hex | 14aa69a0d93 |
1420134321555 has 32 divisors (see below), whose sum is σ = 2524734673920. Its totient is φ = 757389540960.
The previous prime is 1420134321533. The next prime is 1420134321581. The reversal of 1420134321555 is 5551234310241.
1420134321555 is a `hidden beast` number, since 1 + 4 + 201 + 3 + 432 + 15 + 5 + 5 = 666.
It is not a de Polignac number, because 1420134321555 - 27 = 1420134321427 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10207510 + ... + 10345700.
It is an arithmetic number, because the mean of its divisors is an integer number (78897958560).
Almost surely, 21420134321555 is an apocalyptic number.
1420134321555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1420134321555 is a deficient number, since it is larger than the sum of its proper divisors (1104600352365).
1420134321555 is a wasteful number, since it uses less digits than its factorization.
1420134321555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 214328 (or 214322 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 1420134321555 its reverse (5551234310241), we get a palindrome (6971368631796).
The spelling of 1420134321555 in words is "one trillion, four hundred twenty billion, one hundred thirty-four million, three hundred twenty-one thousand, five hundred fifty-five".
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