14201353145033 has 2 divisors, whose sum is σ = 14201353145034. Its totient is φ = 14201353145032.

The previous prime is 14201353145029. The next prime is 14201353145053. The reversal of 14201353145033 is 33054135310241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8905610787529 + 5295742357504 = 2984227^2 + 2301248^2 .

It is a cyclic number.

It is not a de Polignac number, because 14201353145033 - 2² = 14201353145029 is a prime.

It is a super-2 number, since 2×14201353145033² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14201353144984 and 14201353145002.

It is not a weakly prime, because it can be changed into another prime (14201353145003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7100676572516 + 7100676572517.

It is an arithmetic number, because the mean of its divisors is an integer number (7100676572517).

Almost surely, 2^{14201353145033} is an apocalyptic number.

It is an amenable number.

14201353145033 is a deficient number, since it is larger than the sum of its proper divisors (1).

14201353145033 is an equidigital number, since it uses as much as digits as its factorization.

14201353145033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 14201353145033 its reverse (33054135310241), we get a palindrome (47255488455274).

The spelling of 14201353145033 in words is "fourteen trillion, two hundred one billion, three hundred fifty-three million, one hundred forty-five thousand, thirty-three".